# Lesson 15: Adding and Subtracting with Scientific Notation

## 15.1: Number Talk: Non-zero Digits

Mentally decide how many non-zero digits each number will have.

$(3 \times 10^9)(2 \times 10^7)$

$(3 \times 10^9) \div (2 \times 10^7)$

$3 \times 10^9 + 2 \times 10^7$

$3 \times 10^9 - 2 \times 10^7$

## 15.2: Measuring the Planets

Diego, Kiran, and Clare were wondering:

“If Neptune and Saturn were side by side, would they be wider than Jupiter?”

1. They try to add the diameters, $4.7 \times 10^4$ km and $1.2 \times 10^5$ km. Here are the ways they approached the problem. Do you agree with any of them? Explain your reasoning.
1. Diego says, “When we add the distances, we will get $4.7 + 1.2 = 5.9$. The exponent will be 9. So the two planets are $5.9 \times 10^9$ km side by side.”
2. Kiran wrote $4.7 \times 10^4$ as 47,000 and $1.2 \times 10^5$ as 120,000 and added them: \begin{align} 120,\!000& \\ + 47,\!000& \\ \hline 167,\!000& \end{align}

3. Clare says, “I think you can’t add unless they are the same power of 10.” She adds $4.7 \times 10^4$ km and $12 \times 10^4$ to get $16.7 \times 10^4$.
2. Jupiter has a diameter of $1.43 \times 10^5$. Which is wider, Neptune and Saturn put side by side, or Jupiter?

## 15.3: A Celestial Dance

object diameter (km) distance from the Sun (km)
row 1 Sun $1.392 \times 10^6$ $0 \times 10^0$
row 2 Mercury $4.878 \times 10^3$ $5.79 \times 10^7$
row 3 Venus $1.21 \times 10^4$ $1.08 \times 10^8$
row 4 Earth $1.28 \times 10^4$ $1.47 \times 10^8$
row 5 Mars $6.785 \times 10^3$ $2.28 \times 10^8$
row 6 Jupiter $1.428 \times 10^5$ $7.79 \times 10^8$
1. When you add the distances of Mercury, Venus, Earth, and Mars from the Sun, would you reach as far as Jupiter?
1. Add all the diameters of all the planets except the Sun. Which is wider, all of these objects side by side, or the Sun? Draw a picture that is close to scale.

## 15.4: Old McDonald's Massive Farm

Use the table to answer questions about different life forms on the planet.

Row 1 creature number mass of one individual (kg)
Row 2 humans $7.5 \times 10^9$ $6.2 \times 10^1$
Row 3 cows $1.3 \times 10^9$ $4 \times 10^2$
Row 4 sheep $1.75 \times 10^9$ $6 \times 10^1$
Row 5 chickens $2.4 \times 10^{10}$ $2 \times 10^0$
Row 6 ants $5 \times 10^{16}$ $3 \times 10^{\text -6}$
Row 7 blue whales $4.7 \times 10^3$ $1.9 \times 10^5$
Row 8 antarctic krill $7.8 \times 10^{14}$ $4.86 \times 10^{\text -4}$
Row 9 zooplankton $1 \times 10^{20}$ $5 \times 10^{\text -8}$
Row 10 bacteria $5 \times 10^{30}$ $1 \times 10^{\text -12}$
1. On a farm there was a cow. And on the farm there were 2 sheep. There were also 3 chickens. What is the total mass of the 1 cow, the 2 sheep, the 3 chickens, and the 1 farmer on the farm?
2. Make a conjecture about how many ants might be on the farm. If you added all these ants into the previous question, how would that affect your answer for the total mass of all the animals?
3. What is the total mass of a human, a blue whale, and 6 ants all together?
4. Which is greater, the number of bacteria, or the number of all the other animals in the table put together?

## Summary

When we add decimal numbers, we need to pay close attention to place value. For example, when we calculate $13.25 + 6.7$, we need to make sure to add hundredths to hundredths (5 and 0), tenths to tenths (2 and 7), ones to ones (3 and 6), and tens to tens (1 and 0). The result is 19.95.

We need to take the same care when we add or subtract numbers in scientific notation. For example, suppose we want to find how much further the Earth is from the Sun than Mercury. The Earth is about $1.5 \times 10^8$ km from the Sun, while Mercury is about $5.8 \times 10^7$ km. In order to find $$1.5\times 10^8 - 5.8 \times 10^7$$ we can rewrite this as $$1.5 \times 10^8 - 0.58 \times 10^8$$ Now that both numbers are written in terms of $10^8$, we can subtract 0.58 from 1.5 to find $$0.92 \times 10^8$$ Rewriting this in scientific notation, the Earth is $$9.2 \times 10^7$$ km further from the Sun than Mercury.